passing through (3,-1); parallel to the graph of 2x+4y=7

We need to first find the slope of the given line, 2x+4y=7.......rearranging, we have

4y = -2x + 7     divide both sides by 4

y = - 2/4x = 7/4   So, since the lines will be parallel, their slopes will be -2/4 = -1/2

And using our given point and the slope, we have

y - (-1) = -1/2(x - 3)

y + 1 =  -(1/2)x + 3/2      subtract 1 from both sides

y =  -(1/2)x + 1/2

A graph of both lines can be found here.........https://www.desmos.com/calculator/thvvkf3oam