+0  
 
-1
65
2
avatar+52 

Function h is defined as follows: 

  

 

\(h(x) = \left\{ \begin{array}{cl} \lfloor 4x \rfloor & \text{if}~x \le \pi, \\ 3-x & \text{if}~\pi < x \le 5.2, \\ x^2 & \text{if}~x>5.2. \end{array}\right.\)

 

Find h(h( \(\sqrt2\) ))

 Apr 27, 2023
 #2
avatar+118616 
+1

sqrt2 is less than pi

so

 

\(h(\sqrt2)=\lfloor4\sqrt2 \rfloor \\ h(\sqrt2)=\lfloor 5.65 \rfloor \\ h(\sqrt2)=5 \\ now\\ h(5)=\)

 

and you can finish it

 May 6, 2023

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