Function h is defined as follows:
\(h(x) = \left\{ \begin{array}{cl} \lfloor 4x \rfloor & \text{if}~x \le \pi, \\ 3-x & \text{if}~\pi < x \le 5.2, \\ x^2 & \text{if}~x>5.2. \end{array}\right.\)
Find h(h( \(\sqrt2\) ))
sqrt2 is less than pi
so
\(h(\sqrt2)=\lfloor4\sqrt2 \rfloor \\ h(\sqrt2)=\lfloor 5.65 \rfloor \\ h(\sqrt2)=5 \\ now\\ h(5)=\)
and you can finish it
+52 
