+0  
 
0
116
2
avatar

In pentagon ABCDP, AB = BC = CD = 4, angle ABC = anlge BCD = 90, AP = DP, angle APD = 90.  In simple radical form, what is the perimeter of pentagon ABCDP ?

 

 

 Dec 13, 2020
 #1
avatar+11238 
+1

In pentagon ABCDP, AB = BC = CD = 4, angle ABC = anlge BCD = 90, AP = DP, angle APD = 90.  In simple radical form, what is the perimeter of pentagon ABCDP ?

 

Hello Guest!

 

\(p=3\cdot 4+2\cdot \frac{4}{\sqrt{2}}=12+2\cdot \frac{4}{\sqrt{2}}\cdot \frac{\sqrt{2}}{\sqrt{2}}\)

\(p=12+4\cdot\sqrt{2}\)

\(p=4(3+\sqrt{2})=17.657\)

laugh  !

 Dec 14, 2020
 #2
avatar
0

Perimeter    P = √144 + √32 = 17.65685425

 Dec 14, 2020

61 Online Users

avatar
avatar