In pentagon ABCDP, AB = BC = CD = 4, angle ABC = anlge BCD = 90, AP = DP, angle APD = 90. In simple radical form, what is the perimeter of pentagon ABCDP ?
+14915 In pentagon ABCDP, AB = BC = CD = 4, angle ABC = anlge BCD = 90, AP = DP, angle APD = 90. In simple radical form, what is the perimeter of pentagon ABCDP ?
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\(p=3\cdot 4+2\cdot \frac{4}{\sqrt{2}}=12+2\cdot \frac{4}{\sqrt{2}}\cdot \frac{\sqrt{2}}{\sqrt{2}}\)
\(p=12+4\cdot\sqrt{2}\)
\(p=4(3+\sqrt{2})=17.657\)
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