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When the length of a rectangle is increased by 20% and the width increased by \(15\%\), by what percent is the area increased?

 Feb 4, 2022
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The original area is \(l \times w\)

 

The new area is: \(1.2l \times 1.15w = 1.38lw\)

 

So, the area increased by \(\color{brown}\boxed {38\text%}\)

 Feb 4, 2022

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