When the length of a rectangle is increased by 20% and the width increased by \(15\%\), by what percent is the area increased?
+2666 The original area is \(l \times w\)
The new area is: \(1.2l \times 1.15w = 1.38lw\)
So, the area increased by \(\color{brown}\boxed {38\text%}\)
