Three bags of jelly beans contain 26, 28, and 30 beans. The ratios of yellow beans to all beans in each of these bags are 50%, 25%, and 50%, respectively. All three bags of candy are dumped into one bowl. To the nearest percent, what is the percentage of yellow jelly beans in the bowl?
+1223 yellow beans in the first bag = 26 * 50% = 13
yellow beans in the second bag = 28 * 25% = 7
yellow beans in the third bag = 30 * 50% = 15
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all yellow beans in all bags = 13 + 7 + 15 = 35
all beans in all bags = 26 + 28 + 30 = 84
percentage of yellow beans = (35/84) * 100% = 42%
