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Adam, Ben, Cathy and Dana share some lollies. First Adam takes 3/5 of the lollies, then Ben takes 1/4 of the remainder, and then Cath takes1/3 of what is left. Dana gets all the rest. What fraction of the original number of lollies does Dana get

 Mar 28, 2015

Best Answer 

 #2
avatar+111437 
+10

Adam, Ben, Cathy and Dana share some lollies. First Adam takes 3/5 of the lollies, then Ben takes 1/4 of the remainder, and then Cath takes1/3 of what is left. Dana gets all the rest. What fraction of the original number of lollies does Dana get ???

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After Adam takes 3/5 of them there are 2/5 left

Ben takes 1/4 of these, so that means that there are (3/4)(2/5) left = 6/20 = 3/10 left

Cath takes 1/3 of these, so there are (2/3)(3/10) l= 2/10  left for Dana

Check

Adam gets 3/5 = 6/10

Ben gets (1/4)(2/5)  = 1/10

Cath  gets (1/3)(3/10)  = 1/10

Dana gets 2/10

And these all sum to 1

 

  

 Mar 28, 2015
 #1
avatar+1068 
+10

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 Mar 28, 2015
 #2
avatar+111437 
+10
Best Answer

Adam, Ben, Cathy and Dana share some lollies. First Adam takes 3/5 of the lollies, then Ben takes 1/4 of the remainder, and then Cath takes1/3 of what is left. Dana gets all the rest. What fraction of the original number of lollies does Dana get ???

-----------------------------------------------------------------------------------------------------------------------

After Adam takes 3/5 of them there are 2/5 left

Ben takes 1/4 of these, so that means that there are (3/4)(2/5) left = 6/20 = 3/10 left

Cath takes 1/3 of these, so there are (2/3)(3/10) l= 2/10  left for Dana

Check

Adam gets 3/5 = 6/10

Ben gets (1/4)(2/5)  = 1/10

Cath  gets (1/3)(3/10)  = 1/10

Dana gets 2/10

And these all sum to 1

 

  

CPhill Mar 28, 2015

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