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There are 5% fewer girls than boys in a badminton club. Given that there are 4 more boys than girls, find the total number of members in the club.

 

 

Hint: Let the total number of boys be 100%

 Jun 11, 2021
 #1
avatar+121056 
+1

4 boys   must represent  5%  of  the club

 

So....the total members  must  be  4 / 5%    4/.05  =    =   80

 

 

cool cool cool

 Jun 11, 2021
 #2
avatar+315 
0

0.05 * 4 = 0.20

 

1.00 - 0.20 = 0.80

 

80 members in the club

 Jun 11, 2021
 #3
avatar+315 
+1

Wait I did it wrong

 

Let X be the no of boys

No of girls = 0.95X

Also as per question

X = 4 + 0.95X

0.05X = 4

X= 80

No of girls= 0.95 X = 76

Total members in club = 80+76 = 156
 

Bold=Correct 

Tgfromthe4  Jul 7, 2021
 #4
avatar+272 
+1

no. of boys = x ----------------(1)

no. of girls = x -5%*x

                  = x -5/100*x

                =x-x/20

                =19x/20------------------(2)

no. of boys = 19x/20 + 4  ----------------(3)

eqn (1) and (3) are equal to each other

x = 19x/20 + 4

x -19x/20 = 4

x = 4*20

x = 80 (no. of boys)

no. of girls = 80*19/20

                 =4*19 =76

total no of members in club = 80+76 

total no of members in club = 156

 Jul 7, 2021

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