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# Percentage

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There are 5% fewer girls than boys in a badminton club. Given that there are 4 more boys than girls, find the total number of members in the club.

Hint: Let the total number of boys be 100%

Jun 11, 2021

#1
+1

4 boys   must represent  5%  of  the club

So....the total members  must  be  4 / 5%    4/.05  =    =   80   Jun 11, 2021
#2
0

0.05 * 4 = 0.20

1.00 - 0.20 = 0.80

80 members in the club

Jun 11, 2021
#3
+1

Wait I did it wrong

Let X be the no of boys

No of girls = 0.95X

Also as per question

X = 4 + 0.95X

0.05X = 4

X= 80

No of girls= 0.95 X = 76

Total members in club = 80+76 = 156

Bold=Correct

Tgfromthe4  Jul 7, 2021
#4
+1

no. of boys = x ----------------(1)

no. of girls = x -5%*x

= x -5/100*x

=x-x/20

=19x/20------------------(2)

no. of boys = 19x/20 + 4  ----------------(3)

eqn (1) and (3) are equal to each other

x = 19x/20 + 4

x -19x/20 = 4

x = 4*20

x = 80 (no. of boys)

no. of girls = 80*19/20

=4*19 =76

total no of members in club = 80+76

total no of members in club = 156

Jul 7, 2021