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Find the perimter and area of each shape.

 

 

 Mar 15, 2021
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for the first shape, the side EB is 15 - 9 = 6. using the Pythagorean theorem, we can solve for side CB.

 

EB^2 + CE^2 = CB^2

6^2+15^2 = CB^2

36+225 = CB^2

261 = CB^2

CB = sqrt261.

 

now, we can solve the perimeter. 

9+15+15+sqrt(261) = 39 + sqrt261.

 

 

for the second shape, we can simply add all the sides.

 

4+12+14+12+4+9+6+9 = 70.

 

hope this helped! please correct me if i am wrong, or if you are confused about something:)

 Mar 15, 2021

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