+132 for the first shape, the side EB is 15 - 9 = 6. using the Pythagorean theorem, we can solve for side CB.
EB^2 + CE^2 = CB^2
6^2+15^2 = CB^2
36+225 = CB^2
261 = CB^2
CB = sqrt261.
now, we can solve the perimeter.
9+15+15+sqrt(261) = 39 + sqrt261.
for the second shape, we can simply add all the sides.
4+12+14+12+4+9+6+9 = 70.
hope this helped! please correct me if i am wrong, or if you are confused about something:)
