I think the answer is 15*sqrt3+15
Now let me try and explain how I got this.
< KJA = 60° Ext < of a triangle is equal sum of opposite interior angles
triangle JKF is isosceles (2 equal angles) therefore KJ=JF=10
consider triangle AJK
Sin30=1/2=AJ/10 so AJ=5
Using Pythagoras' Theorum
$$AK^2=10^2-5^2
AK^2=100-25
AK^2=75
AK=5\sqrt3$$
AF=5+10=15
$$\\KF^2=15^2+(5\sqrt3)^2\\\\
KF^2=225+75\\\\
KF^2=300\\\\
KF=10\sqrt3\\\\$$
$$\\Perimeter = 5\sqrt3+10\sqrt3+15\\\\
Perimeter = 15\sqrt3+15\;\; units\\\\$$
A triangle has 180 degrees, right. So you add 30+30=60. So, the perimeter is 180 degrees.
Well, I don't know how to find the perimeter of a triangle using degrees.
Converse of the base angle theorem - If two angles of a triangle are congruent, then the sides opposite those angles are congruent
sorry i took so long ive been away but i believe the answer is 41.03 only because if you look at the formula or a diagram for a 30,60,90 triangle the smaller leg is X the second leg is x square root3 and the hypotenuse is 2x using these if you fine the perimeter for KAJ you can also use the same formulas on the larger triangle that you need hope im right lol
I think the answer is 15*sqrt3+15
Now let me try and explain how I got this.
< KJA = 60° Ext < of a triangle is equal sum of opposite interior angles
triangle JKF is isosceles (2 equal angles) therefore KJ=JF=10
consider triangle AJK
Sin30=1/2=AJ/10 so AJ=5
Using Pythagoras' Theorum
$$AK^2=10^2-5^2
AK^2=100-25
AK^2=75
AK=5\sqrt3$$
AF=5+10=15
$$\\KF^2=15^2+(5\sqrt3)^2\\\\
KF^2=225+75\\\\
KF^2=300\\\\
KF=10\sqrt3\\\\$$
$$\\Perimeter = 5\sqrt3+10\sqrt3+15\\\\
Perimeter = 15\sqrt3+15\;\; units\\\\$$
JF = KJ = 10 Sides opposite equal angles are themselves equal
Therefore, m<KJF = 120
m<KJF = 120 Therefore m< KJA = 60 (The sum of any two angles comprising a strainght angle = 180)
Therefore, triangle KAJ is 30 - 60 - 90
And AJ = 5 And KA = 5√3
Then, by the Pytagorean theorem, KF = √[ (AJ + JF)^2 + (KA)^2] = √[ (5 + 10)^2 + (5√3)^2] =
√[ (15)^2 + (5√3)^2] = √[ 15^2 + 75] = √[ 225 + 75] = √[ 300] = 10√3
So....the perimeter = AJ + JF + KF + KA = 5 + 10 + 10√3 + 5√3 =
15 + 15√3