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using the digits 3, 4, 5, 6, 7, 8, and 9, how many 4-digit numbers can be constructed if the number must begin with an odd digit and digits may not be repeated?

Guest May 18, 2017
 #1
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We have four choices for the first digit

And the other digits can be permuted  in  P (6,3) ways  .....so....

 

4 * P(6, 3)  =  480    four  digit numbers

 

 

cool cool cool

CPhill  May 18, 2017
edited by CPhill  May 18, 2017

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