using the digits 3, 4, 5, 6, 7, 8, and 9, how many 4-digit numbers can be constructed if the number must begin with an odd digit and digits may not be repeated?

Guest May 18, 2017


We have four choices for the first digit

And the other digits can be permuted  in  P (6,3) ways  .....so....


4 * P(6, 3)  =  480    four  digit numbers



cool cool cool

CPhill  May 18, 2017
edited by CPhill  May 18, 2017

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