The graphs of \(2y + x + 3 = 0\) and \(3y + ax + 2 = 0\) are perpendicular. Solve for \(a\) .
In the form by + ax + c = 0....the slope is given by
-a / b
So..... let -a/ b be the slope of the first line and since perpendicular lines have negative reciprocal slopes, let b /a be the slope of the second line...so we have
-1/2 = 3 /a
-2 = a / 3
a = -6
See the graph, here : https://www.desmos.com/calculator/2rwoqegwpu