Phillip, Andy, Roger and Jace by candies. Phillip buys twice as many as Jace. Jace buys 7 less than Andy. Andy buys 17 more than Roger. In all, they buy 167 candies. How many did each person buy?
Phillip, Andy, Roger and Jace by candies. Phillip buys twice as many as Jace. Jace buys 7 less than Andy. Andy buys 17 more than Roger. In all, they buy 167 candies. How many did each person buy?
Let x = the number that Roger bought
Let x + 17 = the number Andy bought
Let x + 10 be the number Jace bought {7 less than Andy}
Let 2(x + 10) be the number that Philip bought
So we have
x + ( x + 17) + (x + 10) + 2(x + 10) = 167 simplify
5x + 47 = 167 subtract 37 from each side
5x = 120 divide both sides by 5
x = 24 = Roger's total
x + 17 = 41 = Andy's total
x + 10 = 34 = Jace's total
2(x + 10) = 68 = Philip's total
Check........24 + 41 + 34 + 68 = 167 (√√√)
Phillip, Andy, Roger and Jace by candies. Phillip buys twice as many as Jace. Jace buys 7 less than Andy. Andy buys 17 more than Roger. In all, they buy 167 candies. How many did each person buy?
Let x = the number that Roger bought
Let x + 17 = the number Andy bought
Let x + 10 be the number Jace bought {7 less than Andy}
Let 2(x + 10) be the number that Philip bought
So we have
x + ( x + 17) + (x + 10) + 2(x + 10) = 167 simplify
5x + 47 = 167 subtract 37 from each side
5x = 120 divide both sides by 5
x = 24 = Roger's total
x + 17 = 41 = Andy's total
x + 10 = 34 = Jace's total
2(x + 10) = 68 = Philip's total
Check........24 + 41 + 34 + 68 = 167 (√√√)