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Phillip, Andy, Roger and Jace by candies. Phillip buys twice as many as Jace. Jace buys 7 less than Andy. Andy buys 17 more than Roger. In all, they buy 167 candies. How many did each person buy?

 Feb 5, 2015

Best Answer 

 #1
avatar+130511 
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Phillip, Andy, Roger and Jace by candies. Phillip buys twice as many as Jace. Jace buys 7 less than Andy. Andy buys 17 more than Roger. In all, they buy 167 candies. How many did each person buy?

Let x = the number that Roger bought

Let x + 17 = the number Andy bought

Let x + 10 be the number Jace bought  {7 less than Andy}

Let 2(x + 10) be the number that Philip bought

So we have

x + ( x + 17) + (x + 10) + 2(x + 10) = 167     simplify

5x + 47 = 167      subtract 37 from each side

5x = 120     divide both sides by 5

x = 24  = Roger's total

x + 17 = 41 = Andy's total

x + 10 = 34  = Jace's total

2(x + 10) = 68 = Philip's total

Check........24 + 41 + 34 + 68 = 167 (√√√)

 

 Feb 5, 2015
 #1
avatar+130511 
+10
Best Answer

Phillip, Andy, Roger and Jace by candies. Phillip buys twice as many as Jace. Jace buys 7 less than Andy. Andy buys 17 more than Roger. In all, they buy 167 candies. How many did each person buy?

Let x = the number that Roger bought

Let x + 17 = the number Andy bought

Let x + 10 be the number Jace bought  {7 less than Andy}

Let 2(x + 10) be the number that Philip bought

So we have

x + ( x + 17) + (x + 10) + 2(x + 10) = 167     simplify

5x + 47 = 167      subtract 37 from each side

5x = 120     divide both sides by 5

x = 24  = Roger's total

x + 17 = 41 = Andy's total

x + 10 = 34  = Jace's total

2(x + 10) = 68 = Philip's total

Check........24 + 41 + 34 + 68 = 167 (√√√)

 

CPhill Feb 5, 2015

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