physical science

what is 0 F in degrees Celsius?

\(T_C=\frac59(T_F-32) \qquad T_F=0 \ °F\\ T_C=\frac59(0-32) \\ T_C=\frac59(-32) \\ T_C=\frac{5\cdot (-32)}{9} \\ T_C=-\frac{5\cdot 32}{9} \\ T_C=-\frac{160}{9} \\ T_C=-17.7\overline{7} \ °C\\\)

what is 0 F in degrees Celsius? Tc=5/9(TF-32)

 Tc=5/9(TF-32)

C=5/9(0 - 32)

C=(5 X -32)/9

C=-160/9

C=-17.77777777778..........etc.