Physics 102 part 2 Urgent........

You question doesn't make sense to me for the answers given. Because the period of a pendulum should vary as the square root of the gravity ratio between the Earth and the Moon. That is, if the gravity on Earth is 6 times that on the Moon, then the period on the Moon should be:

Tsqrt(6) =2.46T. But, I don't see that on your list of choices!!. Sorry, unless I'm neglecting something.

Alan should take a look at it.

Hi Damien!

On the Moon, the acceleration of gravity is one sixth of it's value here on earth. If a pendulum has a period of T on here on earth Earth, what will its period be on the Moon?

A.T/

B.T

C.T/6

D.T/3

E.6T

$T= 2\pi \times \sqrt{\frac{l}{g} }$ 

$T_{M} = 2\pi \times \sqrt{\frac{6\times l}{g} }$

T_M = T $\times \sqrt{6}$ = 2.45 T

A. T = T_M / $\sqrt{6}$

The time for one oscillation of the pendulum on the moon is 2.45 times the time of a vibration on the earth.

Greeting asinus :- )

   !