a 3.05 kg block is sliding across the ground with μk=0.250. what is the friction force?
+12528 a 3.05 kg block is sliding across the ground with μk=0.250. what is the friction force?
+36916 3.05 x 9.81 N =3.05*9.81 = 29.9205 N (Normal force)
29.9205 N x .250 = 29.9205*.25 = 7.480125 N Frictional force
