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a 3.05 kg block is sliding across the ground with μk=0.250. what is the friction force?

 May 15, 2019
 #1
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a 3.05 kg block is sliding across the ground with μk=0.250. what is the friction force?

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 May 15, 2019
 #2
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3.05 x 9.81 N =3.05*9.81 = 29.9205 N   (Normal force)

29.9205 N x .250 = 29.9205*.25 = 7.480125 N Frictional force

 May 15, 2019

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