A runner moves 2.88 m/s north. She accelerates at 0.350 m/s^2 at a -52.0 angle. At the point in the motion where she is running directly east, what is Δx?
+36916 The y component of the acceleration is - .350 sin 52 = .=-.2758 m/s^2
When does the y component of the runners motion = 0?
v = v0 + at
0 = 2.88 + (-.2758) t so t = 10.44 sec
What is the speed in the x direction at this point in time?
x component of acceleration = .350 cos 52 = .2155 m/s^2
v in x direction =
v = vo + at
= 0 + .2155 (10.44) = 2.24 m/s
