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A block is on a surface with µs=0.325. it takes 4.11 N to break it free from static friction. How much normal force acts on the block?

 May 15, 2019
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\(F_s = \mu_sN\), where \(F_s = 4.11\) and \(\mu_s = 0.325\)

\(4.11 = (0.325)N\)

\(N = \frac{4.11}{0.325}\)

\(N = 12.65\)

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 May 15, 2019

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