A 15.5 kg block is pulled by two forces. The first is 11.8 N at a 53.7 angle and the second is 22.9 N at a -15.8 angle. What is the magnitude of the acceleration?

Guest May 16, 2019

#1**+2 **

Find the vecor sum of the forces

y direction: 11.8 sin 53.7 + 22.9 sin (-15.8) = 3.27 N

x direction 11.8 cos 53.7 + 22.9 cos(-15.8) = 29.02 N

Net magnitude force = sqrt ( 3.27^2 + 29.02^2) = 29.2 N

F = ma

29.2 = 15.5 a a = 1.88 m/s^2

ElectricPavlov May 17, 2019