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A 15.5 kg block is pulled by two forces. The first is 11.8 N at a 53.7 angle and the second is 22.9 N at a -15.8 angle. What is the magnitude of the acceleration?

 May 16, 2019
 #1
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Find the vecor sum of the forces

y direction:   11.8 sin 53.7 +  22.9 sin (-15.8) = 3.27  N

 

x direction     11.8 cos 53.7 + 22.9 cos(-15.8) = 29.02 N

 

Net magnitude force  = sqrt ( 3.27^2 + 29.02^2) = 29.2 N

 

F = ma

29.2 = 15.5 a      a = 1.88 m/s^2

 May 17, 2019
edited by ElectricPavlov  May 17, 2019

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