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The moon umbriel orbits uranus (mass=8.68 x 10^25 kg) at a distance of 2.66 x 10^8 m. What is umbriel orbital period(in hours)?

 May 23, 2019

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Orbital Period = Kepler's Third Law 
P =2*pi*sqrt(a^3/(G*M)), where a =semi-major axis.
P =2*pi*sqrt(2.66E8^3 / (8.68E25*6.67428E-11))
P = 358130 - seconds
P =358,130 / 3,600 =99.48 - hours

 May 23, 2019
 #1
avatar
0
Best Answer

Orbital Period = Kepler's Third Law 
P =2*pi*sqrt(a^3/(G*M)), where a =semi-major axis.
P =2*pi*sqrt(2.66E8^3 / (8.68E25*6.67428E-11))
P = 358130 - seconds
P =358,130 / 3,600 =99.48 - hours

Guest May 23, 2019

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