1. You take a 50.0 kg block of iron that melts at 1,808 K. All of it melts to liquid at the same temperature (Hf = 2.89 × 10^5 J/kg). What is the change in entropy?
Use the following:
\(\Delta S = \frac{\Delta Q}{T}\\ \Delta Q=50\times 2.89\times 10^5 J\\ T = 1808K\)
