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1. You take a 50.0 kg block of iron that melts at 1,808 K. All of it melts to liquid at the same temperature (Hf = 2.89 × 10^5 J/kg). What is the change in entropy?

 Mar 10, 2020
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Use the following:


\(\Delta S = \frac{\Delta Q}{T}\\ \Delta Q=50\times 2.89\times 10^5 J\\ T = 1808K\)

 Mar 10, 2020

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