#1**+1 **

A. the particle's position is given by the equations in the question....without a time , we cannot tell the particle's position. At t= o it is at 0,6

original velocity vx = 1.3 m/s vy = -3 m/s

Magnitude of this velocity is sqrt (1.3^2 +(-3)^2)) = 3.27 m/s

acceleration ax = -0.3 m/sec^2 ay= 1.3 m/sec^2 Magnitude = 1.334 m/sec^2

B. The x velocity is given by 1.3 -.3t

the y velocity is given by -3 +1.3t set these equal to each other

1.3-.3t = -3+1.3t solve for t

4.3 = 1.6t t= 2.69 seconds when vx and vy are equal

ElectricPavlov
Feb 25, 2018