In physics, if i throw a ball straight up, and it takes 0.01 seconds and starts off the ground 1 m and i need to find the vi, whats the xf? the formula xf=xi+vit+1/2gt^2
xi=1
vi=trying to find
t=0.01
g= 10
so what is the Xi so I can find the Vi?
+36915 xf=xi+vit+1/2gt^2 put in the values you are given
xf = 1 + vi t + 1/2 g t^2 ( I think that should be MINUS 1/2 gt^2)
anyway xi is initial position = 1 m (given)
I am a bit confused as to what you ae looking for? You ask for xi and then vi and then xf and you have a t = .01 (what is that?)
