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In physics, if i throw a ball straight up, and it takes 0.01 seconds and starts off the ground 1 m and i need to find the vi, whats the xf? the formula xf=xi+vit+1/2gt^2

xi=1

vi=trying to find

t=0.01

g= 10

so what is the Xi so I can find the Vi?

 Apr 28, 2020
edited by Guest  Apr 28, 2020
 #1
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xf=xi+vit+1/2gt^2   put in the values you are given

xf = 1  +   vi t + 1/2 g t^2       ( I think that should be  MINUS 1/2 gt^2)

     anyway   xi is initial position = 1 m    (given)

 

I am a bit confused as to what you ae looking for?    You ask for xi    and then vi   and then xf    and you have a t = .01   (what is that?)

 Apr 28, 2020
edited by ElectricPavlov  Apr 28, 2020

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