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An acrobat is launched from a cannon at an angle of 60° above the horizontal. The acrobat is caught by a safety net mounted horizontally at the height from which he was initially launched. Suppose the acrobat is launched at a speed of 26 m/s. T/I

 

(a) How long does it take before he reaches his maximum height?

 

(b) How long does it take in total for him to reach a point halfway back down to the ground?

 

*I understand part A and i got the answer (2.2976) but i'm not sure i understand what part B is asking or how to solve it? please help with steps thank you!*

 Nov 15, 2015
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It would be helpful if you gave us the formula you used for part A.

 Nov 15, 2015

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