how do you solve for t when 0=26sin60t + (1/2)(-9.8)t^2?
I assume this is
0=26(sin60)t + (1/2)(-9.8)t^2 so we have
[ 26sqrt(3)/2] t - 4.9 t^2 = 0 factor out t
t [ 13sqrt(3) - 4.9t ] = 0
Set both factors to 0....... and t = 0 or t = [ 13sqrt(3)] / 4.9 = about 4.595
