I really need help with this question.



Thanks in advance,


bqrs01  Nov 27, 2017

The resistance in the circuit on the right (Rr) is twice that of the circuit on the left (R), so the current (Ir) is half that of the left circuit (I).  Power dissipated is equal to Ir2*Rr , so the power dissipated in the right circuit is given by:  Pr = (I/2)2*(2R)


so Pr = I2*R/2,  but P = I2*R  so Pr = P/2


Alan  Nov 27, 2017
edited by Alan  Nov 27, 2017

6 Online Users

New Privacy Policy

We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive information about your use of our website.
For more information: our cookie policy and privacy policy.