a child riding a sled is pulled down a snowy hill by a force of 75N if the child and the sleds mass is 55kg what is their speed after 7.5 s? assume the child and the sled is initially at rest
I believe the answer is about 10m/s F=ma m=55kg F=75N a=F/m=75/55=(about) 1.36m/s^2 Finally, Vf=Vi+at t=7.5s Vf=(0m/s)+(~1.36m/s^2)(7.5s) =(1.36)x(7.5) =(10.227) (significant digits) Vf=10m/s Hope this helps
I believe the answer is about 10m/s F=ma m=55kg F=75N a=F/m=75/55=(about) 1.36m/s^2 Finally, Vf=Vi+at t=7.5s Vf=(0m/s)+(~1.36m/s^2)(7.5s) =(1.36)x(7.5) =(10.227) (significant digits) Vf=10m/s Hope this helps
Of course... I believe this is only true if we neglect the Force of friction.
