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A simple pendelum has a length of L and a period of 4.25 seconds. What is the new period when the length is increased to 1.25L?
 Aug 12, 2013

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T = 2*Pi*sqrt(L/g)
=> g*[T/(2*Pi)]^2 = L

L_2 = 1.25L = 1.25*g*[T/(2*Pi)]^2

=> T_2 = 2*Pi*sqrt(1.25*g*[T/(2*Pi)]^2/g) = 2*Pi*sqrt(1.25*9.81[m/s²]*[4.24s/(2*Pi)]^2/9.81[m/s²]) = 4.74s
 Aug 12, 2013

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