Solve for t:
120 = 5. t^2 + 10 t
5. t^2 + 10 t = 5 t^2 + 10 t:
120 = 5 t^2 + 10 t
120 = 5 t^2 + 10 t is equivalent to 5 t^2 + 10 t = 120:
5 t^2 + 10 t = 120
Divide both sides by 5:
t^2 + 2 t = 24
Add 1 to both sides:
t^2 + 2 t + 1 = 25
Write the left hand side as a square:
(t + 1)^2 = 25
Take the square root of both sides:
t + 1 = 5 or t + 1 = -5
Subtract 1 from both sides:
t = 4 or t + 1 = -5
Subtract 1 from both sides:
Answer: |t = 4 or t = -6
