+244 To determine the depth of a well, a person holds a penny at rest, drops it, and measures the time it takes for it to hit the water. If the time is 1.4 s, what is the depth of the well? Neglect air resistance.
+36923 x = x0 + vot + 1/2 a t^2 In this instance x0 = original position = 0 vo = original velocity = 0
so you are left with x = 1/2 a t^2 = 1/2 (32) (1.4)^2 = 16 ( 1.96) = 31.36 ft deep (using 'a' = 32)
