physics

V =m/s

but where's the time span on how'll they reach the water?

if someone jumps off a 10.0m high tower, what will their velocity be when they reach the water?

I am going to assume no air or wind resistance and the guy falls (not jumps)
The initial height is 10, the end height is 0

Initially
y''=-g
y' = 0
y=10

ongoing
y'' = -g
y' = -gt
y = -gt ² / 2 + 10

when y=0
0 = -gt ² / 2 +10
....
t = sqrt20 / sqrtg
so
y' = -g * sqrt20 / sqrtg

y' = - sqrt(20g)

If g is approx 9.8m/s ² then y' is approx = -14

So at impact the speed will be 14m/s