Raj through a baseball at 3.20m/s at an angle of 55 degrees to the ground. How far away from her did the baseball land?
+130477 We need to find the time the ball traveled
We can use this equation :
0 = 3.20sin(55)t - 4.9t^2 divide through by t
0 = 3.20sin(55) - 4.9t add 4.9t to both sides
4.9t = 3.20sin(55) divide both sides by 4.9
t = 3.20sin(55)/ 4.9 = about .535s
So.....the horizontal displacement is given by :
d = 3.2cos(55)(.535) = about 0.982 m
+130477 We need to find the time the ball traveled
We can use this equation :
0 = 3.20sin(55)t - 4.9t^2 divide through by t
0 = 3.20sin(55) - 4.9t add 4.9t to both sides
4.9t = 3.20sin(55) divide both sides by 4.9
t = 3.20sin(55)/ 4.9 = about .535s
So.....the horizontal displacement is given by :
d = 3.2cos(55)(.535) = about 0.982 m
