An archer shoots an arrow at 63.2 m/s at a 42.0 degree angle. If the ground is flat, how far away does it land?
The horizontal displacement is given by v0^2 * sin (2* θ) / g where v0 = 63.2 m/s , θ = 42° and g = 9.8 m/s
So we have
[63.2]^2 * sin (2 * 42°) / 9.8 =
405.3 m