Physics

Guest:

In a hydrogen atom, the electron in orbit
around the proton feels an attractive force of
about 8.02 × 10−8 N.
If the radius of the orbit is 5.61 × 10−11 m,
what is the frequency?
Answer in units of rev/s

I found a few physics pages including this one but I really don't know.
I suggest that you post your question in
physicshelpforum.com
or
mathhelpforum.com.

With both of them, you will need to join before you can post anything (they are free)
When you post you will be expect to talk a little about what you already know or what you have tried.
They don't like it if they think you haven't thought about your own question yet.
Having said that these forums are full of very helpful and knowledgabe people.
If they think you are making an effort they will bend over backwards to help you learn.

http://answers.yahoo.com/question/index?qid=20111208185158AAbSQ7s
http://www.physicsclassroom.com/calcpad/circgrav/prob24

I hope that you get you question sorted.

Hmm, shouldn't the attractive force be equal to the centripetal force mv^2 / r?
And suppose it takes a time T to complete an orbit, doesn't that mean that we cover a distance vT?
At the same time, a complete orbit is 2πr.

We should be able to get the frequency f=1/T from that...