If Luis pulls straight down on the end of a wrench that is tilted θ = 30∘ above the horizontal and is r = 39 cm long, what force must he apply to exert a torque of -15 N⋅m ?
Use F*cos(30°)*0.39 = -15 The F is in Newtons, r is in m (i.e. it's 0.39m). The cos(30°) makes sure we are using the component of force that is perpendicular to the lever arm.
