A 2.45 mg rain drop falls to the ground. As it is falling, what magnitude of force does it exert on the earth and what is the resulting acceleration of the earth due to this force?
A 2.45 mg rain drop falls to the ground. As it is falling, what magnitude of force does it exert on the earth and what is the resulting acceleration of the earth due to this force?
Force=Mass X Acceleration
2.45mg=2.45 X 10^-7 kg. Acceleration due to pull of gravity=9.81 m/sec^2, so we have:
F=M X A
F=(2.45 X 10^-7) X 9.81=2.40345 X 10^-6 newtons of force exerted by the rain drop.
Acceleration=Force/Mass. Mass of the Earth=5.972 X 10^24 kg.
A=(2.40345 X 10^-6) / (5.972 X 10^24)=4.0245 X 10^-31 m/sec^2-acceleration of Earth due to rain drop!!.
