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A powerplant burns coal at 830 K and exhausts to air 288 K. If it runs at the Carnot Efficiency (e=1-(Qc/Qh)), how much input heat must be fed into the plant to produce 230000 J of work? 

 Jan 16, 2017
 #1
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Here is my stab at it:

 

1- Qc/Qh =~ 1 - 288/830 = .653    or  65.3 % effeicient      (the  Carnot effic =  (Th-Tc)/Th  )

65.3/100 = 230000/x

x = 353846 j    input needed

 Jan 16, 2017
edited by ElectricPavlov  Jan 16, 2017
 #2
avatar+37097 
0

Here is my stab at it:

 

1- Qc/Qh = 1 - 288/830 = .653    or  65.3 % effeicient

65.3/100 = 230000/x

x = 352214 j    input needed       (Note: slight change in final answer calculation)

ElectricPavlov  Jan 17, 2017

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