+0

# physics

0
381
3

Calculate the resistance of a conductor with a length of 0.50 meters, a cross-sectional area of 0.02 m^2, and a resistivity of 1.20 x 10 ^ -8 Ohm-meters.

off-topic
Aug 9, 2017

#1
0

Resistance(q)=Restitivity(R)*Length(L)/Area(A)

R=0.000000012 ohms per meter per mm^2

L=0.5 meters

A=20000mm^2

Resistance=0.000000012*0.5/20000

Resistance=0.0000000000003 ohms OR 3*10^-13 ohms

Aug 9, 2017
#3
+1280
+2

This is an incredible presentation of incompetent SLOP: Wrong definition of the electrical resistance constant, wrong units for cross-sectional area, and wrong answer.

Classification: BatShìt-Stupìd.

------

R=0.000000012 ohms per meter per mm^2  <---- The symbol is ρ (rho) and the unit is the ohm-meter. (There is no “per” in this constant.)

L=0.5 meters <---  This should be 0.50. The trailing zero determines the precision of the measurement.

A=20000mm^2 <--- This unit is wrong. This should remain in meters because the constant is defined in meters.

----------------

Formula: RL=ρL/A

(0.50)(1.2E-8)/(0.02) = (3.0E-7) ohms @ 20°C <--- The constant is calculated at 20°C

------------

Mr. BB, stick to simple interest rate computations—my cat says you usually get those right.

Aug 10, 2017
edited by GingerAle  Aug 10, 2017