A custodianpulls a vacuum 13.5 m with a 33.9 N force at a 55.0 degree angle, against a 14.2 N friction force. Find the total work done on the vacuum.
W=Fd(cos)(theta)
W=fd(cos)(theta)
+14985 A custodianpulls a vacuum 13.5 m with a 33.9 N force at a 55.0 degree angle, against a 14.2 N friction force. Find the total work done on the vacuum.
Please not so complicated.
The whole work is applied force times stretch.
\(W=F\times s = 33.9 N \times 13.5m=457.65 Nm\)
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