For integers \(n\), let \(f(n) = \left\{ \begin{array}{cl} n^2 & \text{ if }n\text{ is odd}, \\ n^2 - 4n - 1 & \text{ if }n\text{ is even}. \end{array} \right.\)Find \(f(f(f(f(f(4)))))\) .
Is the answer 1, since 1^2 repeats?
f(4) = -1
f ( f (4) ) = f (-1) = 1
f ( f ( f (4) ) ) = f (1) = 1
f ( f ( f ( f (4) ) ) ) = f(1) = 1
f ( f ( f ( f ( f (4) ) ) ) ) = f (1) = 1
Correct, mathtoo...!!!!
Thank you, CPhill!
+816 
