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Hi guys, thanks for the help,

 

Let 
\(f(x) = \begin{cases} k(x) &\text{if }x>0, \\ -\frac1{2x}&\text{if }x< 0\\ 0&\text{if }x=0. \end{cases} \)

Find the function k(x) such that f(x) is its own inverse.

 

Thanks again guys, -Evancool

 Sep 23, 2019
 #1
avatar+139 
+1

Is there anyone?

 Sep 23, 2019

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