If
\(f(x) = \begin{cases} x^2-4 &\quad \text{if } x \ge -4, \\ x + 3 &\quad \text{otherwise}, \end{cases}\)
then for how many values of x is f(f(x))=5?
I got one value for x; -6. That wasn't correct.
The graph below should help:
For how many values of x is f(f(x))=5?
thank you omi67 and alan!!!