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If

\(f(x) = \begin{cases} x^2-4 &\quad \text{if } x \ge -4, \\ x + 3 &\quad \text{otherwise}, \end{cases}\)

then for how many values of x is f(f(x))=5?

 

I got one value for x; -6. That wasn't correct. 

 Mar 18, 2020
 #1
avatar+29984 
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The graph below should help:

 

 Mar 18, 2020
 #2
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For how many values of x is f(f(x))=5?

laugh

 Mar 18, 2020
edited by Omi67  Mar 18, 2020
 #3
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thank you omi67 and alan!!!

 Mar 18, 2020

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