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If

\[f(x) =
\begin{cases}
x^2-4 &\quad \text{if } x \ge -4, \\
x + 3 &\quad \text{otherwise},
\end{cases}
\]

then for how many values of $x$ is $f(f(x)) = 5$?

 Feb 21, 2021
 #1
avatar
0

The equation f(f(x)) = 5 has three solutions.

 Feb 21, 2021

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