+0  
 
+1
66
1
avatar+147 

If

\[f(x) =
\begin{cases}
x^2-4 &\quad \text{if } x \ge -4, \\
x + 3 &\quad \text{otherwise},
\end{cases}
\]

then for how many values of $x$ is $f(f(x)) = 5$?

 Feb 15, 2021
 #1
avatar
0

There are 3 values of x such that f(f(x)) = 5.

 Feb 16, 2021

19 Online Users

avatar