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# Piecewise-Defined Functions

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If

$f(x) = \begin{cases} x^2-4 &\quad \text{if } x \ge -4, \\ x + 3 &\quad \text{otherwise}, \end{cases}$

then for how many values of $x$ is $f(f(x)) = 5$?

Feb 15, 2021

### 1+0 Answers

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There are 3 values of x such that f(f(x)) = 5.

Feb 16, 2021