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An aeroplane is flying horizontally at a height 3150 mt. above a horizontal plane ground. At a particular instant, it passes another aeroplane vertically below it. At this instant, the angles of elevation of the planes from a point on the ground are 30 degrees and 60 degrees. Find the distance between the two planes at that instant.

 Jun 22, 2020
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Tan 60 = opp/ adj = 3150/d      d= 1818.65

 

tan 30 = opp/ adj = height / 1818.65      Height of second plane = 1050 meters

 

now you can find the distance between the two planes because you have both of their altitudes.....

 Jun 22, 2020

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