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Mark bought \(222\) meters of fencing to enclose an area of pasture for his sheep. He plans to use all of the fencing to make a rectangle twice as long as it's wide. Let \(\ell\) = length; \(w\) = width.

 

Find the length (in meters) of the area he plans to fence in.

 Dec 13, 2017
 #1
avatar+98196 
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Let the width   = W

Then the length is twice as much  = 2W

 

And perimeter  = 2  [ W + L ]  =  2 [ W + 2W ]

 

So

 

222 = 2 [ W + 2W ]

 

222  = 2  [ 3W]

 

222  =  6W          divide both sides by 6

 

37  =  W

 

And the length is twice this  =   2 * 37   =    74 m

 

 

cool cool cool

 Dec 13, 2017
edited by CPhill  Dec 13, 2017

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