+112 Simplify \(\sqrt[4]{256a^2b^4}\).
\(\color{green}\boxed{{\color{navy}x}~{\color{lightblue}x}^{\color{navy}y}~{\color{black}\frac{\color{navy}x}{\color{navy}y}}~\color{black}\sqrt{\color{navy}x}~~{\color{navy}+~~-~\times}}\)
\(\color{red}\boxed{{\color{black}\sqrt[\color{navy}y]{\color{lightblue}x}}}\)
+37146 4 x 4 x 4 x 4 = 256
=4ba^(1/2)
I do not know what the rest of your question means.....
+118678 I beg to differ just a little EP
By convention the answer must be positive and we do not know if a or b is pos or neg.
\(\sqrt[4]{256a^2b^4}\\ =\sqrt[2]{16|a|b^2}\\ =4\sqrt{|a|}|b|\\ =|\;4b\sqrt{|a|}\;|\\ or\\ =|\;4b|a|^{1/2}\;|\\\)
+37146 Agree ! Melody is correct.... ! I was thinking about a^2 and b^4 both being POSITIVE results...but that does not tell us if a or b are positive themselves !
