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A line contains the points \((a,b)\) and \((a+3,b+3)\). Find the equation of the line in terms of \(a\) and \(b\) in point-slope form, and then convert it to slope-intercept form.
(a, b) (a + 3, b+ 3)
The slope is [ b + 3 - b ] / [ a + 3 - a ] = 3 / 3 = 1
y - b = 1 ( x - a)
y = x - a + b
y = x + (b - a)