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If tan x = 6/g and sin x = 6/h, what is the value of cos x?

 

 Apr 21, 2020
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tan x = \(\frac{6}{g}\) so the side opposite to x is 6 and the adjacent side (Not the hypotenuse) is g

sin x =\(\frac{6}{h}\) so the side opposite to x is 6 (already know) and the hypotenuse is h

so

cos x = \(\frac{g}{h}\) (adjacent/hypotenuse) 

 Apr 21, 2020

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