If tan x = 6/g and sin x = 6/h, what is the value of cos x?
tan x = \(\frac{6}{g}\) so the side opposite to x is 6 and the adjacent side (Not the hypotenuse) is g
sin x =\(\frac{6}{h}\) so the side opposite to x is 6 (already know) and the hypotenuse is h
so
cos x = \(\frac{g}{h}\) (adjacent/hypotenuse)
