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If tan x = 6/g and sin x = 6/h, what is the value of cos x?

Apr 21, 2020

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tan x = $$\frac{6}{g}$$ so the side opposite to x is 6 and the adjacent side (Not the hypotenuse) is g

sin x =$$\frac{6}{h}$$ so the side opposite to x is 6 (already know) and the hypotenuse is h

so

cos x = $$\frac{g}{h}$$ (adjacent/hypotenuse)

Apr 21, 2020