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Define $f(x) = \frac{x^2 + 2x + 3}{x}$ and $g(x) = x^3 + 2$. Evaluate $g(f(x))$ when $x = -3$.

Oct 13, 2021

#1
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g(f(-3)) = -9.

Oct 13, 2021
#2
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wrong

Oct 13, 2021
#3
+114812
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1) I answered something similar today, have you bothered to look?

2) If you present your question properly more people are likely to respond.

3)  What have you tried for yourself?

Oct 13, 2021