Define $f(x) = \frac{x^2 + 2x + 3}{x}$ and $g(x) = x^3 + 2$. Evaluate $g(f(x))$ when $x = -3$.

g(f(-3)) = -9.

wrong

1) I answered something similar today, have you bothered to look?

2) If you present your question properly more people are likely to respond.

3) What have you tried for yourself?