+0  
 
+1
90
1
avatar

 

In right △ABC , the right angle is at C, m∠A=30∘ , and AC=5√ 5 units.

What is the perimeter of △ABC ?

 Mar 3, 2020
 #1
avatar+108 
+1

Using the 30-60-90 right triangle theorum,

the hypothenuse is 5 sqrt(5) 

BC is the 5 sqrt(5) / 2

AC is then 5 sqrt(15) / 2

add them up and you get 

15 sqrt(5) / 2 + 5 sqrt(15) / 2

 Mar 3, 2020

16 Online Users